Current transformers · Burden · Saturation
CT Burden Calculator
Add the lead wire, the meter or relay and the connections. See whether the total stays within the CT rating, or whether a C class CT will saturate on a fault.
By Allen Tan · Updated · How results are sourced
1Check
2Burden on the secondary
Stranded, uncoated copper at 75 C (NEC Chapter 9, Table 8).
Distance from the CT to the meter or relay. The tool doubles it for the return path.
From the device data sheet.
Terminals, shorting blocks, test switches. Enter 0 if unknown.
3CT rating
The burden on the CT nameplate, for example 0.3 B-0.5.
Shows the current the meter will see.
The connected burden is 66% of the rated burden, so the CT stays within its accuracy class.
Total burden
0.328 ohm
8.2 VA at 5 A
- Leads (12 AWG, 2 x 50 ft)
- 0.198 ohm
- Meter or relay
- 0.08 ohm
- Connections
- 0.05 ohm
Against B-0.5
- Rated burden
- 0.5 ohm (12.5 VA at 5 A)
- Burden used
- 66%
- Headroom
- 0.172 ohm
- Secondary current at 480 A
- 4 A
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The link carries the full calculation, so anyone opening it lands on the same inputs and the same result.
Standard metering burdens
IEEE C57.13-2016 Table 10, for a 5 A secondary at 60 Hz. For other secondary ratings the impedance stays the same and the VA changes with the current squared.
| Burden | Resistance (ohm) | Inductance (mH) | Impedance (ohm) | VA at 5 A | Power factor |
|---|---|---|---|---|---|
| B-0.1 | 0.09 | 0.116 | 0.1 | 2.5 | 0.9 |
| B-0.2 | 0.18 | 0.232 | 0.2 | 5 | 0.9 |
| B-0.5 | 0.45 | 0.58 | 0.5 | 12.5 | 0.9 |
| B-0.9 | 0.81 | 1.04 | 0.9 | 22.5 | 0.9 |
| B-1.8 | 1.62 | 2.08 | 1.8 | 45 | 0.9 |
Metering accuracy classes
IEEE C57.13-2016 Table 8: limits of the transformer correction factor, with the metered load at 0.6 to 1.0 power factor lagging.
| Class | At 100% rated current | At 10% rated current |
|---|---|---|
| 0.3 | 0.9970 to 1.0030 | 0.9940 to 1.0060 |
| 0.6 | 0.9940 to 1.0060 | 0.9880 to 1.0120 |
| 1.2 | 0.9880 to 1.0120 | 0.9760 to 1.0240 |
Standard relaying burdens and C classes
IEEE C57.13-2016 Table 13, 5 A secondary. The terminal voltage is the C class number: 20 times 5 A times the burden. Ratio error limits for C and T classes are 3% at rated current and 10% at 20 times rated current.
| Burden | Terminal voltage (V) | Impedance (ohm) | VA at 5 A | Power factor |
|---|---|---|---|---|
| B-0.1 | 10 | 0.1 | 2.5 | 0.9 |
| B-0.2 | 20 | 0.2 | 5 | 0.9 |
| B-0.5 | 50 | 0.5 | 12.5 | 0.9 |
| B-1.0 | 100 | 1 | 25 | 0.5 |
| B-2.0 | 200 | 2 | 50 | 0.5 |
| B-4.0 | 400 | 4 | 100 | 0.5 |
| B-8.0 | 800 | 8 | 200 | 0.5 |
On a multi-ratio CT the C class applies to the full winding. The rating of a tap is proportional to the tap ratio over the full ratio, so a C400 1200:5 CT used on the 600:5 tap is 200 V (SEL paper cited below).
Lead wire resistance
NEC Chapter 9, Table 8: stranded, uncoated copper, direct-current resistance at 75 C. Lead resistance is two times the one-way length, because current flows out and back.
| Size | Ohm per 1000 ft | Round trip, 100 ft one way (ohm) |
|---|---|---|
| 14 AWG | 3.14 | 0.628 |
| 12 AWG | 1.98 | 0.396 |
| 10 AWG | 1.24 | 0.248 |
| 8 AWG | 0.778 | 0.156 |
| 6 AWG | 0.491 | 0.098 |
| 4 AWG | 0.308 | 0.062 |
CT ratio chart: typical single-ratio CT ratings
From the example ratings in IEEE C57.13-2016 Table 9, with a 5 A secondary. The standard says other ratings may be agreed between manufacturer and user, so this is not a closed list.
| Ratio | Turns ratio | Secondary at rated primary |
|---|---|---|
| 5:5 | 1:1 | 5 A |
| 10:5 | 2:1 | 5 A |
| 15:5 | 3:1 | 5 A |
| 20:5 | 4:1 | 5 A |
| 25:5 | 5:1 | 5 A |
| 30:5 | 6:1 | 5 A |
| 40:5 | 8:1 | 5 A |
| 50:5 | 10:1 | 5 A |
| 60:5 | 12:1 | 5 A |
| 75:5 | 15:1 | 5 A |
| 100:5 | 20:1 | 5 A |
| 150:5 | 30:1 | 5 A |
| 200:5 | 40:1 | 5 A |
| 250:5 | 50:1 | 5 A |
| 300:5 | 60:1 | 5 A |
| 400:5 | 80:1 | 5 A |
| 500:5 | 100:1 | 5 A |
| 600:5 | 120:1 | 5 A |
| 750:5 | 150:1 | 5 A |
| 800:5 | 160:1 | 5 A |
| 1000:5 | 200:1 | 5 A |
| 1200:5 | 240:1 | 5 A |
| 1500:5 | 300:1 | 5 A |
| 1600:5 | 320:1 | 5 A |
| 2000:5 | 400:1 | 5 A |
| 2500:5 | 500:1 | 5 A |
| 3000:5 | 600:1 | 5 A |
| 4000:5 | 800:1 | 5 A |
| 5000:5 | 1000:1 | 5 A |
| 6000:5 | 1200:1 | 5 A |
| 8000:5 | 1600:1 | 5 A |
| 10000:5 | 2000:1 | 5 A |
| 12000:5 | 2400:1 | 5 A |
Safety. A current transformer secondary must not be open while the primary is energized. IEEE C57.13 warns that hazardous peak voltages may result. Short the secondary before you disconnect the burden.
Sources.IEEE Std C57.13-2016, IEEE Standard Requirements for Instrument Transformers;SEL: Sizing Current Transformers for Line Protection Applications for the saturation criteria; NFPA 70 Chapter 9, Table 8 (values checked against the 2017 edition). Results are an aid for checking a design, not a substitute for the device data sheet or an engineer’s review. Remanent flux is not included. Checked on 2026-10-08.
Questions people actually ask
What does a CT ratio of 400/5 mean?
It means 400 A in the primary produces 5 A in the secondary, a turns ratio of 80:1. Divide the secondary current by 5 and multiply by 400 to get the primary current: a meter reading 1.5 A on the secondary means 120 A in the primary. The same arithmetic applies to 200/5 (40:1), 1200/5 (240:1) and any other ratio in the chart below.
How do I choose a CT ratio from a transformer kVA?
Work out the full-load current first. For a three-phase transformer it is kVA x 1000 divided by (1.732 x line-to-line volts). A 500 kVA transformer at 480 V draws about 601 A. Pick a standard ratio whose primary rating is at or above that current, here 800:5, or check the rating factor on the nameplate of a 600:5 CT before using it. The utility or the meter specification may require a particular ratio.
What does CT class 0.5 mean?
It is an accuracy class, but 0.5 is not one of the metering classes in IEEE C57.13-2016 Table 8, which lists classes such as 0.3, 0.6 and 1.2. A 0.5 class appears on CTs built to other standards. This tool publishes no limits for it, so read the limits from the CT data sheet.
How do I calculate CT burden?
Add the resistance of the lead wires, the meter or relay burden converted to ohms, and the connection resistance. Lead resistance is twice the one-way length times the wire resistance per foot. A device burden in VA converts to ohms as VA divided by the rated secondary current squared. Compare the total with the burden on the CT nameplate.
What does a CT rating such as 0.3 B-0.5 mean?
It is the metering accuracy class followed by the highest standard burden at which that class holds. IEEE C57.13 says a rating of 0.3 B-1.8 implies 0.3 at B-0.1, B-0.2, B-0.5, B-0.9 and B-1.8. A rating written for one burden only, such as 0.3 @ B-0.5, is not guaranteed at the others.
What does C200 mean on a current transformer?
C200 is a relaying class. The CT delivers 200 V to a standard burden at 20 times rated current without more than 10% ratio error. For a 5 A secondary the standard burden is 2 ohm, so 20 x 5 A x 2 ohm = 200 V. The C means leakage flux does not noticeably affect the ratio, so performance can be calculated from the excitation curve.
What is the difference between a metering CT and a relaying CT?
A metering CT is rated for accuracy at 100% of rated current and at 10% (or 5% for some classes) of it. A relaying CT is rated for how far it can carry fault current before it saturates. IEEE C57.13 limits ratio error for C and T classes to 3% at rated current and 10% at 20 times rated current.
What is the knee point of a CT?
For CTs with non-gapped cores, IEEE C57.13 defines the knee of the excitation curve as the point where the tangent is at 45 degrees to the abscissa. IEC 61869-2 defines the knee differently, so check which standard a published knee-point value follows before comparing it with another.
Can I open the secondary of a CT?
No. IEEE C57.13 states that current transformers should never be operated with the secondary circuit open because hazardous peak voltages may result. Short the secondary before disconnecting the burden.
Why does the tool use stranded copper at 75 C?
Those are the NEC Chapter 9 Table 8 values for stranded, uncoated copper at 75 C. Real leads run cooler or hotter, and solid wire is slightly lower. For long runs or tight margins, use the measured loop resistance.
Does the tool add burdens as a vector sum?
No. It adds resistances, which is a conservative arithmetic sum. Real burdens have different power factors, so a result within a few percent of the rating needs a closer check with the device data sheet.
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